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Working with Text |
You need to locate character boundaries if your application allows the end-user to highlight individual characters, or to move a cursor through text a character at a time. To create aBreakIteratorthat locates character boundaries, you invoke thegetCharacterInstancemethod:This type ofBreakIterator characterIterator = BreakIterator.getCharacterInstance(currentLocale);BreakIteratordetects boundaries between user characters, not just Unicode characters. User characters differ with language, but theBreakIteratorclass can recognize these differences because it is locale-sensitive. A user character may be composed of more than one Unicode character. For example, the user character ü can be composed by combining the Unicode characters '\u0075' (u) and '\u00a8' (¨). This isn't the best example, however, because the character ü may also be represented by the single Unicode character '\u00fc'. We'll draw upon the Arabic language for a more realistic example.In Arabic the word for house is:
Although this word contains three user characters, it is composed by six Unicode characters:The Unicode characters at positions 1, 3, and 5 in theString house = "\u0628" + "\u064e" + "\u064a" + "\u0652" + "\u067a" + "\u064f";housestring are diacritics. In Arabic diacritics are required, because they can alter the meanings of words. The diacritics in the example are non-spacing characters since they appear above the base characters. In an Arabic word processor, you cannot move the cursor on the screen once for every Unicode character in the string. Instead, you must move it once for every user character, which may be composed by more than one Unicode character. Therefore, you must use aBreakIteratorto scan the user characters in the string.The sample program,
BreakIteratorDemo.java, creates aBreakIteratorto scan Arabic characters. The program passes thisBreakIterator, along with theStringobject created previously, to a method namedlistPositions:TheBreakIterator arCharIterator = BreakIterator.getCharacterInstance(new Locale ("ar","SA")); listPositions (house,arCharIterator);listPositionsmethod uses aBreakIteratorto locate the character boundaries in the string. Note that theBreakIteratorDemoassigns a particular string to theBreakIteratorwith thesetTextmethod. The program retrieves the first character boundary with thefirstmethod, and then invokes thenextmethod until the constantBreakIterator.DONEis returned. The code for this routine is as follows:Thestatic void listPositions(String target, BreakIterator iterator) { iterator.setText(target); int boundary = iterator.first(); while (boundary != BreakIterator.DONE) { System.out.println (boundary); boundary = iterator.next(); } }listPositionsmethod prints out the following boundary positions for the user characters in the stringhouse. Note that the positions of the diacritics (1, 3, 5) are not listed:0 2 4 6
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Working with Text |