A simple probabability charge satisfies

- probability charge
- p(B)=1 for some finite B in algebra, A.

Theorem: P a simple probability charge on A => A contains all singletons /\ P(x)=0 forall but a finite number of x in X /\ forall B in A: P(B)=Sum(x in B, P(x)).

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jl@crush.caltech.edu index

convex_continuation

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