02/21/2002
15-462 Graphics I
19
Construction of Bezier Subdivision
•Use algebraic reasoning
•l(0) = l0 = p0
•l(1) = l3 = p(1/2) = 1/8(p0 + 3p1 + 3p2 + p3)
•l’(0) = 3(l1 – l0) = p’(0) = 3/2 (p1 – p0)
•l’(1) = 3(l3 – l2)
= p’(1/2) = 3/8(-p0 – p1 + p2 +p3)
•Note parameter substitution v = 2u so dv = 2du
