Server: Netscape-Enterprise/2.0a Date: Wed, 13 Nov 1996 23:15:08 GMT Content-type: text/html
Question 2.1 Cost effectiveness is performance per dollar of cost, and the performance will depend on the workload choice.
Cost effectiveness can be measured in the numbers of executions per second per dollar of machine cost:
executions per second per dollar =
executions per second per dollar for S1 =
executions per second per dollar for S2 dollars =
So System 2 is more cost effective. By a ratio of
executions per second per dollar for S1 =
executions per second per dollar for S2 =
So System 1 is slightly more cost effective, by a factor of
executions of P2 per hour =
executions of P2 per hour on S1 =
executions of P2 per hour on S2 =
Hence we can conclude that S2 has higher throughput.
Cost per run per hour for P2 in dollars:
For S1 = = 18.76
For S2 = = 23.07
Hence S1 is more cost effective for this workload.
Harmonic Mean (HM) =
mean of times =
mean of times =
Therefore, HM =
A schematic of a possible solution to the state machine problem. The waveform of the simulation of this schematic.